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s^2-47s-504=0
a = 1; b = -47; c = -504;
Δ = b2-4ac
Δ = -472-4·1·(-504)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-65}{2*1}=\frac{-18}{2} =-9 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+65}{2*1}=\frac{112}{2} =56 $
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